see excel spreadsheet. This your answer
A credit card company claims that the mean credit card debt for individuals is greater than $ 5000. You want to test this claim. You find that a random sample of 30 cardholders has a mean credit card balance of $ 5202 and a standard deviation of $ 600. At alpha equals 0.01, can you support the claim? Complete parts (a) through (e) below. Assume the population is normally distributed.
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A credit card company claims that the mean credit card debt for individuals is greater than $ 5000. You want to test this claim. You find that a random sample of 30 cardholders has a mean credit card balance of $ 5202 and a standard deviation of $ 600. At alpha equals 0.01, can you support the claim? Complete parts (a) through (e) below. Assume the population is normally distributed.
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c = 0.95. x = 9.2. a = 0.4. and n = 59 A 95% confidence interval for p...

A credit card company claims that the mean credit card debt for individuals is greater than $ 5000. You want to test this claim. You find that a random sample of 30 cardholders has a mean credit card balance of $ 5202 and a standard deviation of $ 600. At alpha equals 0.01, can you support the claim? Complete parts (a) through (e) below. Assume the population is normally distributed.
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see excel spreadsheet. This your answer

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You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 60 home theater systems has a mean price of $140. Assume the population standard deviation is $15.40 Construct a 90% confidence interval for the population mean. The 90% confidence interval is (nothing,nothing).
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