In a random sample of 25 people, the mean commute time to work was 30.4 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a tdistribution to construct a 99 confidence interval for the population mean muμ. What is the margin of error of muμ? Interpret the results.
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In a random sample of 25 people, the mean commute time to work was 30.4 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a tdistribution to construct a 99 confidence interval for the population mean muμ. What is the margin of error of muμ? Interpret the results.
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Construct the confidence interval for the population mean u.
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c = 0.95. x = 9.2. a = 0.4. and n = 59 A 95% confidence interval for p...

In a random sample of 25 people, the mean commute time to work was 30.4 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a tdistribution to construct a 99 confidence interval for the population mean muμ. What is the margin of error of muμ? Interpret the results.
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A random sample of 75 eighth grade students’ scores on a national mathematics assessment test has a mean score of 278. This test result prompts a state school administrator to declare that the mean score for the state’s eighth graders on this exam is more than 275. Assume that the population standard deviation is 36. At alphaequals0.12, is there enough evidence to support the administrator’s claim? Complete parts (a) through (e).
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see excel spreadsheet. This your answer

Use the confidence interval to find the margin of error and the sample mean.
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(0.264,0.460) The margin of error is 0.098.The sample mean is .3620.



You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 60 home theater systems has a mean price of $140. Assume the population standard deviation is $15.40 Construct a 90% confidence interval for the population mean. The 90% confidence interval is (nothing,nothing).
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