Use the given confidence interval to find the margin of error and the sample mean. (13.6,22.8)
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Use the given confidence interval to find the margin of error and the sample mean. (13.6,22.8)
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A credit card company claims that the mean credit card debt for individuals is greater than $ 5000. You want to test this claim. You find that a random sample of 30 cardholders has a mean credit card balance of $ 5202 and a standard deviation of $ 600. At alpha equals 0.01, can you support the claim? Complete parts (a) through (e) below. Assume the population is normally distributed.
russellc, , Statistics, 0
see excel spreadsheet. This your answer
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Use the confidence interval to find the margin of error and the sample mean.
russellc, , Statistics, 0
(0.264,0.460) The margin of error is 0.098.The sample mean is .3620.
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Use the given statement to represent a claim. Write its complement and state which is Upper H 0 and which is Ha. p < 0.55
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Part A is the answer. A. Pick the opposite of the "equation" see excel spreadsheet. This your answer B....
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In a survey of 641 males ages 18-64, 394 say they have gone to the dentist in the past year. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. The 90% confidence interval for the population proportion p is The 95% confidence interval for the population proportion p is Interpret your results of both confidence intervals. Which interval is wider?
russellc, , Statistics, 0 -
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Find the margin of error for the given values of c, sigma, and n.
russellc, , Statistics, 0
c = 0.95. a = 2.1, n = 36 Answer 0.686